Suppose radius of the moon's orbit around the earth is doubled. Its period around the earth will become:
A
1/2 times
B
times
C
2 2/3 times
D
2 3/2 times
Text Solution
Verified by ExpertsThe correct answer is:
D
According to Kepler's law
T 2 ∝ R 3
(Here: R is orbital radius and T is time period)
Now according to question when orbital radius is doubled, then period will be
T2 = 23/2 T1
(Here ; R 1 = R, R 2 = 2R)
Hence, the time period will become 2 3/2 times.
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